In a game two players A and B take turns in throwing a pair of fair dice starting with player A and total of scores on the two dice, in each throw in noted. A wins the game if he throws a total of 6 before B throws a total of 7 and B wins the game if the throws a total of 7 before A throws a total of six. The game stops as soon as either of the players wins. The probability of A winning the game is:
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a
3161
b
531
c
3061
d
56
answer is C.
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Detailed Solution
Problability of getting a total of 6 is 536 Probability of of getting a total of 7 is 636P(A win) =P(6)+P(7)P(7)P(6)+P(6¯)P(7¯)P(6¯)P(7¯)P(6)+.... =P(6)1+P(6¯)P(7¯)+... =536·11-31363036 =3031
In a game two players A and B take turns in throwing a pair of fair dice starting with player A and total of scores on the two dice, in each throw in noted. A wins the game if he throws a total of 6 before B throws a total of 7 and B wins the game if the throws a total of 7 before A throws a total of six. The game stops as soon as either of the players wins. The probability of A winning the game is: