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a
x=(2n+1)π,n∈Z
b
x=2nπ,n∈Z
c
x=nπ,n∈Z
d
none of these
answer is A.
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Detailed Solution
cosxcos6x=−1 or 2cosxcos6x=−2 or cos7x+cos5x=−2 or cos7x=−1 and cos5x=−1The value of x satisfying these two equations simultaneously and lying between 0 and 2π isπ. Therefore, the general solution is x=2nπ+π,n∈Zthus, x=(2n+1)π,n∈Z