The general solution of the differential equation y(1−xy)dx=x(1+xy)dy is
lnxy=xy+c
lny/x=xy+c
logxy=x+y+c
ydx-xy2dx=xdy+x2ydy
ydx−xdy=xy(xdy+ydx)ydxxy-xdyxy=xdy+ydx⇒∫dxx−dyy=∫d(xy)⇒logxy=xy+c