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General solution of the equation $1 + \cos 3 θ = 2 \cos 2 θ$ is

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θ=nπ±π6,x=2nπ

θ=2nπ±π6,x=nπ

θ=nπ±π3,x=nπ2

θ=nπ±π4,x=nπ

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detailed solution

Correct option is A

1+cos3θ=2cos2θ⇒1+4cos3θ−3cosθ=2(2cos2θ−1)⇒4cos3θ−4cos2θ−3cosθ+3=0⇒(cosθ−1)(4cos2θ−3)=0⇒cosθ=1 or cos2θ=34=322=cos2π6⇒θ=2nπ or θ=nπ±π6,n∈z

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General solution of the equation 1+cos3θ=2cos2θ is

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General solution of the equation $1 + \cos 3 θ = 2 \cos 2 θ$ is