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Q.

General solution of equation 7cos2θ+3sin2θ=4 is

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a

θ=nπ±π6,n∈z

b

θ=nπ±π4,n∈z

c

θ=nπ±π3,n∈z

d

θ=nπ±π2,n∈z

answer is C.

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Detailed Solution

7cos2θ+3sin2θ=4      ⇒4cos2θ+3cos2θ+3sin2θ=4⇒4cos2θ+3=4⇒4cos2θ=1⇒cos2θ=14=122 ⇒sin2θ=34 ⇒sinθ=±32⇒θ=nπ±π3,n∈z
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General solution of equation 7cos2θ+3sin2θ=4 is