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General solution of equation $7 \cos^{2} θ + 3 \sin^{2} θ = 4$ is

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θ=nπ±π6,n∈z

θ=nπ±π4,n∈z

θ=nπ±π3,n∈z

θ=nπ±π2,n∈z

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detailed solution

Correct option is C

7cos2θ+3sin2θ=4 ⇒4cos2θ+3cos2θ+3sin2θ=4⇒4cos2θ+3=4⇒4cos2θ=1⇒cos2θ=14=122 ⇒sin2θ=34 ⇒sinθ=±32⇒θ=nπ±π3,n∈z

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General solution of equation 7cos2θ+3sin2θ=4 is

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General solution of equation $7 \cos^{2} θ + 3 \sin^{2} θ = 4$ is