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Questions  

General solution of the equation tanx=3

a
x=nπ−π3,n∈z
b
x=nπ+π3,n∈z
c
x=nπ+2π3,n∈z
d
x=nπ−2π3,n∈z

detailed solution

Correct option is A

tanx=−3⇒tanx=tan−π3⇒x=nπ−π3,n∈z

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