The general solution of tan5x−tan4x1+tan5xtan4x=1 is
nπ+π4,∀n∈Z
nπ±π4,∀n∈Z
ϕ
nπ=π6,∀n∈Z
tan5x−tan4x1+tan5xtan4x=1⇒ tan(5x−4x)=1⇒ tanx=1⇒ x=nπ+π4,n∈Z