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Questions  

General solution of tan2x+13tanx3=0 is

a
nπ+π6
b
nπ+π4
c
nπ+π2
d
nπ+π3,nπ−π4

detailed solution

Correct option is D

We have tan2x+1−3tanx−3=0⇒tanx=3   or   tanx=−1⇒x=nπ+π3or      x=nπ−π4

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The solution of tanx+tan2x+tan3x=tanxtan2xtan3x is 


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