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Questions  

General solution of trigonometric equation1cosx=sinx

a
nπ±π2
b
2nπ±π2
c
2n+1π2 or 2nπ
d
no solution

detailed solution

Correct option is C

1−cosx=sinx, here sinx≥0⇒x∈2nπ,2n+1πAlso   1−cosx=sin2x⇒1−cosx=1−cos2x⇒cos2x−cosx=0⇒cosx=0  or  cosx=1⇒x=nπ+π2 or x=2nπ

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