General solution of trigonometric equation1−cosx=sinx

1−cosx=sinx, here sinx≥0⇒x∈2nπ,2n+1πAlso   1−cosx=sin2x⇒1−cosx=1−cos2x⇒cos2x−cosx=0⇒cosx=0  or  cosx=1⇒x=nπ+π2 or x=2nπ