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Q.

The general term of (99)5 is

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a

Cr 5(100)5−2r

b

(−1)r Cr 5(100)5−r

c

Cr 5(100)5−r

d

(−1)r Cr 5(−100)5−r

answer is B.

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Detailed Solution

(99)5=(100-1)5 The general term of (a+b)n is Tr+1=Cr nan-rbr Here a=100,b=-1,n=5∴Tr+1=Cr 5(100)5-r(-1)r =(-1)r Cr 5(100)5-r

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The general term of (99)5 is