Given A=(1,1) and AB is any line through it cutting the x-axis in B. if AC is perpendicular to AB and meets the y-axis in C, then the equation of locus of midpoint P of BC is
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a
x+y=1
b
x+y=2
c
x+y=2xy
d
2x+2y=1
answer is A.
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Detailed Solution
Equation of line AB is y−1=m(x−1)Equation of line AC is y−1=−1m(x−1)2h=1−1m2k=1+1mEliminating m we have locus x+y=1