Questions
Given that
detailed solution
Correct option is A
Since, α, β, γ, δ are in H.P., 1/α, 1/β, 1/γ, 1/δ are in A.P. And they may be taken as a−3d, a−d, a+d, a+3d. Replacing x by 1/x, we get the equation whose roots are 1/α, 1/β, 1/γ, 1/δ. Therefore, equation x2−4x+A=0 has roots a−3d, a+d and equation x2−6x+B=0 has roots a−d, a+3d. Sum of the roots is 2(a−d)=4, 2(a+d)=6 ∴ a=5/2, d=1/2 Product of the roots is (a−3d)(a+d)=A=3 (a−d)(a+3d)=B=8Similar Questions
Suppose are in A.P. and Let then are in
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