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$Given A \equiv (1, 1) and A B is any line through it cutting the x -axis at B . If A C is perpendicular to A B and meets the$
$y -axis in C, then the equation of the locus of midpoint P o f B C i s$

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x+y=1

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Correct option is A

The equation of line AB is y−1=m(x−1) . Therefore, the equation of line AC is y−1=−1m(x−1)2h=1−1m2k=1+1m Eliminating m , we have locus x+y=1 .

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Given A≡(1,1) and AB is any line through it cutting the x -axis at B . If AC is perpendicular to AB and meets the y -axis in C , then the equation of the locus of midpoint Pof BC is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

$Given A \equiv (1, 1) and A B is any line through it cutting the x -axis at B . If A C is perpendicular to A B and meets the$
$y -axis in C, then the equation of the locus of midpoint P o f B C i s$