Given that aα2+2bα+c≠0and that the system of equations (aα+b)x+ay+bz=0,(bα+c)x+by+cz=0,(aα+b)y+(bα+c)z=0has a non trivial solution, then a,b,care in
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a
A.P
b
G.P
c
H.P
d
A.G.P
answer is B.
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Detailed Solution
The condition for a homogeneous system of equations to have a non-trivial solution is Δ=0⇒Δ=aα+babbα+cbc0aα+bbα+c=0 R3→R3−(αR1+R2)⇒aα+babbα+cbc-aα2+2bα+c00=0 ⇒-aα2+2bα+cac-b2=0 ⇒ac-b2=0 ∵aα2+2bα+c≠0 ⇒b2=ac ⇒a,b,c are in G.P.