Given,f(x)=0x2−sin xcos x−2sin x−x201−2x2−cos x2x−10' then ∫f(x)dx is equal to
x33−x2sin x+sin 2x+C
x33−x2sin x−cos 2x+C
x33−x2cos x−cos 2x+C
None of the above
We have,
⇒ f(x)=0x2−sin xcos x−2sin x−x201−2x2−cos x2x−10f(x)=0sin x−x22−cos xx2−sin x02x−1cos x−21−2x0
[interchanging rows and columns]
⇒f(x)=(−1)30x2−sin xcos x−2sin x−x201−2x2−cos x2x−10
[taking (-1) common from each column]
⇒ f(x)=−f(x)⇒f(x)=0⇒ ∫f(x)dx=c