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Q.

Given the family of lines, a(2x+y+4)+b(x−2y−3)=0.Among the lines of the family, the number of lines situated at a distance of 10 from the point M(2,−3) is

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a

0

b

1

c

2

d

answer is D.

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Detailed Solution

The point of intersection of the two lines are  (-1, -2).Distance PM = 10Hence the required line is one which passes through (−1,−2)  and is ⊥ to P.M.
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