In the given figure, a parabola is drawn to pass through the vertices B, C and D of the square are ABCD .If the coordinates of A and C are (2,1) and (2,3), respectively, then focus of this parabola is
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a
(1,11/4)
b
(2,11/4)
c
(3,13/4)
d
(2,13/4)
answer is B.
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Detailed Solution
AC is parallel to y axis, its mid point is (2,2) . Thus, B≡(3,2) and D≡(1,2) . Equation of parabola is (x−2)2=λ(y−3) . It passes through (3,2), so λ=−1 . Thus, equation of parabola reduces to (x−2)2=−(y−3) . Hence, axis is (x−2)2 and latus rectum line is y−3=−1/4 . For focus, x−2=0 and y−3=−1/4 . Therefore, focus is (2,11/4) .
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In the given figure, a parabola is drawn to pass through the vertices B, C and D of the square are ABCD .If the coordinates of A and C are (2,1) and (2,3), respectively, then focus of this parabola is