Given the following two statements:(S1):(q∨p)→(p↔∼q) is a tautology. S2:∼q∧(~p↔q) s a fallacy. Then

Given statement (S1):(q∨p)→(p↔∼q) is a tautology. For S1:S1 is not a tautology, so S1, is not correct.Now, S2:(~q)∧((~p)↔q) is a fallacy. For S2:S2 is not a tautology, so S2, is not correct.Hence, option (a) is correct.