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Q.

Given limx→0 f(x)x2=2 where [.] denotes the greatest integer function, then

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a

limx→0fx=0

b

limx→0fx=1

c

limx→0f(x)x does not exist

d

limx→0f(x)xexists

answer is A.

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Detailed Solution

Since   x2>0   and  limit  equala  2,  fx  must  be  a  positive  quantity.   Also,  since  limx→0  fxx2=2.,denominator  →   zero  and   limit  is  finite.   Therefore,  fx  must  be  approaching  zero  or    limx→0  fx=0+. Hence,    limx→0  fx=0+.        limx→0+  fxx=  limx→0+  xfxx2=0and   limx→0-  fxx=  limx→0-  xfxx2=-1Hence,   limx→0  fxx  does  not  exist.
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