Q.
Given limx→0 f(x)x2=2 where [.] denotes the greatest integer function, then
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a
limx→0fx=0
b
limx→0fx=1
c
limx→0f(x)x does not exist
d
limx→0f(x)xexists
answer is A.
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Detailed Solution
Since x2>0 and limit equala 2, fx must be a positive quantity. Also, since limx→0 fxx2=2.,denominator → zero and limit is finite. Therefore, fx must be approaching zero or limx→0 fx=0+. Hence, limx→0 fx=0+. limx→0+ fxx= limx→0+ xfxx2=0and limx→0- fxx= limx→0- xfxx2=-1Hence, limx→0 fxx does not exist.
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