First slide

Means - A.M/G.M/H.M

Question

Given that n AM’s are inserted between two sets of numbers a, 2b and 2a, b where $a, b \in R$ suppose further that the nth mean between these sets of numbers is same then the ratio a:b=

Moderate

A

1:n
B

n:1
C

n+1:1
D

n+2:n-1

Solution

$1 + (\frac{2 b - a}{n + 1}) n = 2 a + (\frac{b - 2 a}{n + 1}) n \Rightarrow a = n b$

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