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Given that n AM’s are inserted between two sets  of numbers a, 2b and 2a, b where a,bR  suppose further  that the nth mean between these sets of numbers is same then the ratio a:b=

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a
1:n
b
n:1
c
n+1:1
d
n+2:n-1

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detailed solution

Correct option is B

1+2b−an+1n=2a+b−2an+1n⇒a=nb


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