Given positive integer r>1,n>2 and the coefficient of (3r)th and (r+2)th terms in the binomial expansion of (1+x)2n are equal. Then
n=2r
n=3r
n=2r+1
none of these
We have
2nC3r−1=2nCr+1⇒3r−1+r+1=2n⇒2r=n