Given three vectors a→,b→ and c→ two of which are non-collinear. Further if (a→+b→) is collinear with c→,(b→+c→) is collinear with, a→,|a→|=|b→|=|c→|=2. Find the value of a→⋅b→+b→⋅c→+c→⋅a→
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a
3
b
-3
c
0
d
cannot be evaluated
answer is B.
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Detailed Solution
a→+b→=λc→---i and b→+c→=μa→---ii∴ (λc→−a→)+c→=μa→ (putting b→=λc→−a→)⇒ (λ+1)c→=(μ+1)a→⇒ λ=μ=−1⇒ a→+b→+c→=0 or |a→|2+|b→|2+|c→|2+2(a→⋅b→+b→⋅c→+c→⋅a→)=0 or a→⋅b→+b→⋅c→+c→⋅a→=−3