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Given two bags A and B follows: bag A contains 3 red and 2 white balls and bag B contains 2 red and 5 white balls. A bag is selected at random, a ball is drawn and put into the other bag, and then a ball is drawn from the second bag. The probability that both balls drawn are of the same color is

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a
1871680
b
9011680
c
4391680
d
None

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detailed solution

Correct option is B

The whole event consists of the following mutually exclusive ways.(1) Selecting the bag A, drawing a red ball from A and putting it into bag B and then drawing a red ball from B.(2) Selecting the bag A, drawing a white ball from A and putting it into bag B and then drawing a white ball from B.(3) Selecting the bag B, drawing a red ball from B and putting it into A and then drawing a red ball from A.(4) Selecting the bag B, drawing a white ball from B and putting it into A and then drawing a white ball from A.The required probability is =12×35×38+12×25×34+12×27×23+12×57×12                                                 =980+320+221+528=9011680


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