Given 0≤x≤12 then the value of tansin−1x2+1−x22−sin−1x is
-1
1
13
3
Put x=sinθ then sin−1x2+1−x22 =sin−112sinθ+12cosθ=sin−1sinθ+π4=θ+π4∴given expression =tanθ+π4−θ=tanπ4=1