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Q.

Given x,y∈R, x2+y2>0. Then the range of x2+y2x2+xy+4y2 is

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a

10−4530,10+4530

b

10−4515,10+4515

c

5−4515,5+4515

d

20−4515,20+4515

answer is B.

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Detailed Solution

λ=x2+y2x2+xy+4y2=1+yx21+yx+4yx2=1+z21+z+4z2              (Putting y/x=z)or   λ+λz+4λz2=1+z2z2(4λ−1)+z(λ)+λ−1=0Since z is real,    D≥0∴    λ2−44λ2−5λ+1≥0∴    15λ2−20λ+4≤0∴    λ∈10−4515,10+4515
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