Q.
Given x,y∈R, x2+y2>0. Then the range of x2+y2x2+xy+4y2 is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
10−4530,10+4530
b
10−4515,10+4515
c
5−4515,5+4515
d
20−4515,20+4515
answer is B.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
λ=x2+y2x2+xy+4y2=1+yx21+yx+4yx2=1+z21+z+4z2 (Putting y/x=z)or λ+λz+4λz2=1+z2z2(4λ−1)+z(λ)+λ−1=0Since z is real, D≥0∴ λ2−44λ2−5λ+1≥0∴ 15λ2−20λ+4≤0∴ λ∈10−4515,10+4515
Watch 3-min video & get full concept clarity