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Given that Z2−Z+1=0,&'Z' is a complex number. If the value of (Z+1Z)2+(Z2+1Z2)2+.......+(Z24+1Z24)2 is λ then the least integer greater than or equal to λπ2 is

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answer is 5.

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Detailed Solution

z=ω or ω2⇒given exp =16−12+822=16+32⇒λ=48

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