First slide

Means - A.M/G.M/H.M

Question

Of 6 GM’s are inserted between 2 and 12 3^rd GM

Moderate

A

$2 (6^{3 / 7})$
B

$2 (6^{4 / 73})$
C

$6^{\frac{5}{7}}$
D

${2.6}^{3 / 5}$

Solution

$2, G_{1} G_{2} \dots \dots G_{6}, 12 are in GP$
$\begin{array}{l} 12 = t_{8} = a r^{7} \\ 12 = 2 r^{7} \Rightarrow r^{7} = 6 \Rightarrow r = 6^{1 / 7} \\ G_{3} = t_{4} = a r^{3} = 2 \cdot 6^{3 / 7} \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App