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Of 6 GM’s are inserted between  2 and 12 3rd GM

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a
263/7
b
264/73
c
657
d
2.63/5

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detailed solution

Correct option is A

2, G1G2……G6,12 are in GP 12=t8=ar712=2r7⇒r7=6⇒r=61/7G3=t4=ar3=2⋅63/7


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