Q.

The gradient of the curve y=be−x/a where it crosses the y-axis is

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a

ba

b

ab

c

−ab

d

−ba

answer is D.

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Detailed Solution

y=be−x/a−(1) Given (1) crosses y-axis⇒ put x=0 ⇒y=b (1) cuts the y-axis at (0,  b) Gradient=(dydx)(o,b)=−bae−x/a=−ba
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The gradient of the curve y=be−x/a where it crosses the y-axis is