Q.
The gradient of the curve y=be−x/a where it crosses the y-axis is
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a
ba
b
ab
c
−ab
d
−ba
answer is D.
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Detailed Solution
y=be−x/a−(1) Given (1) crosses y-axis⇒ put x=0 ⇒y=b (1) cuts the y-axis at (0, b) Gradient=(dydx)(o,b)=−bae−x/a=−ba
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