The graph of a function f(x) is as follows then

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limx→1−f(x)=1

limx→1+f(x)=−1

limx→1f(x) exists

limx→1f(x) does not exists

answer is D.

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Detailed Solution

From graph limx→1-f(x)=-1 and limx→1+f(x)=0

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