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The greatest common divisor is
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a
31
b
2
c
17
d
none of these
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Correct option is A
We have, for 3≤r≤29r!(31−r)! 31Cr=31!As the prime 31 divides R.H.S. and 31 does not divide r! and(31−r)! for β≤r≤29, we get 31∣ 31CrAlso, Since 31C29=(31)(3)(5),31C3=(31)(29)(5) and 31C5=(31)(29)(7)No prime other than 31 can divide all the numbers.Thus greatest common divisors of the given numbers is 31 .Similar Questions
is equal to
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