The greatest and least values of sin−1x3+cos−1x3 are
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a
−π2,π2
b
−π38,π38
c
π332,7π38
d
none of these
answer is C.
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Detailed Solution
We have, sin−1x3+cos−1x3 =sin−1x+cos−1x3−3sin−1xcos−1xsin−1x+cos−1x =π38−3sin−1xcos−1xπ2=π38−3π2π2−sin−1xsin−1x =π38−3π24sin1x+3π2sin−1x2 =π38+3π2sin−1x2−π2sin−1x=π38+3π2sin−1x−π42−3π332=π332+3π2sin−1x−π42So, the least value of sin−1x3+cos−1x3 is π332 sin−1x−π42≤3π42∴ Greatest value =π332+9π216×3π2=7π38