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a
20C5125
b
20C515
c
20C5
d
20C5(5)
answer is A.
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Detailed Solution
We have Tr+1=20Cr5(5)r=20Cr1(5)r−1Suppose (r + 1)th term is the greatest term. ThenTr+1Tr>1 and Tr+1Tr+2>1⇒20−rr+115>1 and r+219−r5>1⇒20−r>5r+5 and r5+25>19−r⇒19−25<(5+1)r<20−5⇒14(19−25)(5−1)