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Q.

The greatest value of the function F(x) = ∫4x t2−8t+16dt on [0,5] is

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a

5

b

1/3

c

4

d

2/3

answer is B.

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Detailed Solution

F′(x)=x2−8x+16=(x−4)2>0 for x∈[0,5]−{4}So the greatest value of F is F(5)=∫45 (t−4)2dt=13

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