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The greatest value of the function $F (x) =$
$\int_{4}^{x} (t^{2} - 8 t + 16) d t on [0, 5]$ is

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Correct option is B

F′(x)=x2−8x+16=(x−4)2>0 for x∈[0,5]−{4}So the greatest value of F is F(5)=∫45 (t−4)2dt=13

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The greatest value of the function F(x) = ∫4x t2−8t+16dt on [0,5] is

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The greatest value of the function $F (x) =$
$\int_{4}^{x} (t^{2} - 8 t + 16) d t on [0, 5]$ is