The greatest value of the term independent of x, as a varies over R, in the expansion of xcosα+sinαx20is
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a
20C10
b
20C15
c
20C19
d
20C101210
answer is D.
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Detailed Solution
Tr+1, the (r+1)thterm in the expansion of xcosα+sinαx20is 20Cr(xcosα)20−rsinαxr =20Crx20−2r(cosα)20−r(sinα)rFor this term to be independent of x, we set 20–2r=0 ⇒ r=10.Let β=Term independent of x, then β=20C10(cosα)10(sinα)10 =20C10[cosαsinα]10Thus, the greatest possible value of β is 20C101210.