For a> b> c > 0, the distance between (1, 1) and the point of intersection of the lines ax + by + c = 0 and bx + ay + c = 0 is less than 22. then

Solving given lines for their point of intersection, we get the point of intersection as-ca+b,-ca+b, Its distance from ( 1 , 1) is1+ca+b2+1+ca+b2<22 or (a+b+c)2<4(a+b)2 or (a+b+c)2−(2a+2b)2<0 or (c−a−b)(c+3a+3b)<0 Since a>b>c>0,(c−a−b)<0 or a+b−c>0