For a>0,≠1 the roots of the equation logaxa+logxa2+loga2xa3=0 are given by
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a
a−4/3
b
a−3/4
c
a
d
a−1/2
answer is A.
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Detailed Solution
logaxa+logxa2+loga2xa3=0 or 1logaax+2logax+3logaa2x=0 or 11+logax+2logax+32+logax=0 Let logax=y, we have 1y+1+2y+32+y=0 or 6y2+11y+4=0 or y=logax=−12,−43⇒ x=a−4/3,a−1/2