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Q.

For a>0,≠1 the roots of the equation logax⁡a+logx⁡a2+loga2x⁡a3=0 are given by

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a

a−4/3

b

a−3/4

c

a

d

a−1/2

answer is A.

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Detailed Solution

logax⁡a+logx⁡a2+loga2x⁡a3=0 or  1loga⁡ax+2loga⁡x+3loga⁡a2x=0 or  11+loga⁡x+2loga⁡x+32+loga⁡x=0 Let loga⁡x=y, we have 1y+1+2y+32+y=0 or  6y2+11y+4=0 or  y=loga⁡x=−12,−43⇒ x=a−4/3,a−1/2
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For a>0,≠1 the roots of the equation logax⁡a+logx⁡a2+loga2x⁡a3=0 are given by