First slide
Theory of equations
Question

For a > 0, the roots of the equation logaxa+logxa2+loga2xa3=0 are given by:

Moderate
Solution

We have,

logaalogaa+logax+2logaalogax+3logaa2logaa+logax=0

  11+t+2t+32+t=0 (letlogax=t)  2t+t2+2t2+6t+4+3t2+3tt(1+t)(2+t)=0  6t2+11t+4=0   6t2+8t+3t+4=0         logax=12,43  x=a1/2,a4/3

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