For a > 0, the roots of the equation logaxa+logxa2+loga2xa3=0 are given by:
a−4/3
a−3/4
a1/2
a−1
We have,
logaalogaa+logax+2logaalogax+3logaa2logaa+logax=0
⇒ 11+t+2t+32+t=0 (letlogax=t) ⇒ 2t+t2+2t2+6t+4+3t2+3tt(1+t)(2+t)=0 ⇒ 6t2+11t+4=0 ⇒ 6t2+8t+3t+4=0 ⇒ logax=−12,−43 ⇒ x=a−1/2,a−4/3