he solution curve of the differential equation, 1+e-x1+y2dydx=y2 , which passes through the point (0,1), is :

Given equation is 1+y2y2dy=ex1+exdx    variables separable method⇒∫1y2+1dy=∫exdx1+ex⇒-1y+y=ln1+ex+C It passes through (0,1)-1+1=ln2+C⇒C=-ln2 Equation of curve y-1y=ln1+ex-ln2⇒y2-1=yln1+ex2