First slide
Applications of trigonometry
Question

The height of the tower vertically at the orthocenter of the triangle (of sides a, b, c) and subtending A at A is

Difficult
Solution

If H is the orthocenter and h is the height of the tower then

tanA=hAH and AH=2RcosA

  h2RcosA=tanA           h=2RsinA=a

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