Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

In a high school, a committee has to be formed form a group of 6 boys M1,M2,M3,M4,M5,M6  and 5girls G1,G2,G3,G4,G5i) Let α1be the total number of ways in which the committee can be formed such that the committee has 5 members, having exactly 3 boys and 2 girlsii) Let α2 be the total number of ways in which the committee can be formed such that the committee has at least 2 members, and having an equal number of boys and girlsiii) Let α3 be the number of ways in which the committee can be formed such that the committee has 5 numbers, at least 2 of them being girlsiv) Let α4  be the total number of ways in which the committee can be formed such that the committee has 4 members, having at lest 2 girls and such that both and are NOT in the committee together.            LIST-I                                                                                      LIST-II            P. The value of α1  is                                                               1.136            Q. The value of α2 is                                                               2. 189            R. The value of α3 is                                                               3. 192                                     S. The value of α4 is                                                              4. 200                                                                                                          5. 381                                                                                                          6. 461

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

P-4;Q-6;R-2;S-1

b

P-4;Q-2;R-3;S-1

c

P-1;Q-4;R-2;S-3

d

P-4;Q-6;R-5;S-2

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

(1) α1=6352=200 So P→4 (2) α2=6151+6252+6353+6454+6555=115−1=46!  So Q→6 (3) α3=5263+5362+5461+5560=115−5065−5164=381  So R→5 (4) α2=5262−4151+5361−4211+54=189 So S→2
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring