Questions
How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions?
detailed solution
Correct option is C
The four digits 3, 3, 5, 5 can be arranged at four even places in 4!2!2!=6 ways and the remaining digits viz., 2, 2, 8, 8, 8 can be arranged at the five odd places in 5!2!3!=10 ways.Thus, the number of possible arrangements is (6) (10) = 60.Similar Questions
The number of ways in which we can get at least 6 successive tails when a coin is tossed 10 times in a row, is
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