Questions
How many different nine digit numbers can be formed from the number 22 33 55 8 88 by rearranging its digits so that the odd digits occupy even positions?
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a
16
b
36
c
60
d
180
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Correct option is C
The four digits 3, 3, 5, 5, can be arranged at four even places in 4!2!2!=6 ways and the remaining digits viz., 2, 2, 8, 8, 8 can be arranged at the five odd places in 5!2!3!=10 ways.Thus, the number of possible arrangements is (6) (10) = 60.Similar Questions
The number of ways in which we can get at least 6 successive tails when a coin is tossed 10 times in a row, is
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