First slide

Permutations

Question

How many even numbers of 3 different digits can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition of digits is not allowed)?

Moderate

A

224
B

280
C

324
D

None of these

Solution

The number will be even, if last digit is either 2, 4, 6 or 8
i.e. the last digit can be filled in 4 ways and remaining two digits can be filled in $^{8} P_{2}$ , ways.
Hence, required number of numbers of three different digits = $^{8} P_{2} \times 4 = 224$

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