Q.

How many even numbers of 3 different digits can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition of digits is not allowed)?

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a

224

b

280

c

324

d

None of these

answer is A.

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Detailed Solution

The number will be even, if last digit is either 2, 4, 6 or 8i.e. the last digit can be filled in 4 ways and remaining two digits can be filled in  8P2, ways.Hence, required number of numbers of three different digits = 8P2×4=224
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