First slide

Combinations

Question

In how many ways can a team of 11 players be formed out oi 25 players, if 6 out of them are always to be included and 5 always to be excluded

Moderate

A

2020
B

2002
C

2008
D

8002

Solution

Since 5 players are always to be excluded and 6 players always to be included, therefore 5 players are to be chosen from 14. Hence, required number of ways it $^{14} C_{5} = 2002$ .

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