Questions
points?
a
1,−12
b
32,12
c
12,0
d
−32,1
detailed solution
Correct option is B
Equation of the given ellipse in the standard form as x24+y3=1 It implies a=2,b=3 and e=1-32=12 Focus =(±1,0) For hyperbola a=12 and foci are same as foci of ellipse, so that a2e2=1⇒e2=2⇒b2=a2=12 Hyperbola x2a22-y2b22=1⇒x2-y2=12Verify the options, option (2) will not satisfy the above equation.Talk to our academic expert!
Similar Questions
The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal to half of the distance between its foci, is:
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