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$I = \int e^{3 \log x} {(x^{4} + 1)}^{- 1} d x$

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logx4+1+C

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detailed solution

Correct option is B

I=∫e3logx(x4+1)-1dx =∫elogx3(x4+1)-1dx =14∫4x3(x4+1)dx =14log(x4+1)+C

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