If In=∫(ln x)ndx then In+nIn-1 =
(ln x)nx
x(ln x)n-1
x(ln x)n
None of these
In=∫ln xn.1 dxIntegrating by parts =xln xn−∫x n ln xn−1xdx =xln xn−nIn−1∴In+nIn−1=xln xn