If P is a constant, fx=x2x3x4236PP2P3 andf"x=0 has roots α,β ,then
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a
α and β have opposite sign and equal magnitude at p=3
b
at p = 0, f"x=0 represents an identity
c
At P=2, product of the roots is unity
d
at p=−3 product of roots of f"x=0 is negative
answer is A.
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Detailed Solution
f"x=26x12x2236pp2p3=0Expand the determinant⇒ 122p2−3px2−6x2p3−6p+6p2p−2=0⇒ 12p2p−3x2−12pp2−3+6p2p−2=0At P=0, its an identityAt P=3,ba=0,so roots are opposite in sign and equal in magnitudeAt P=2,ca=0, so product of the roots is zero. At P=−3,ca=6p2p−212p2p−3 negativeSo product of the roots is negative