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Questions  

If p is the length of the perpendicular from the origin to the line xa+yb=1 then

a
1a2+1b2=1p2
b
1a2+1b2=2p2
c
1a2-1b2=1p2
d
1a2+1b2=p2

detailed solution

Correct option is A

The perpendicular distance from origin to the line ax +by +c=0 is ca2+b2 The distance from origin to the line xa+yb=1 is p given p=11a2+1b2 take reciprocals and then squaring both sides  1a2+1b2=1p2

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