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if 3+14(3+P)+142(3+2P)+143(3+3P)+....=8then the value of P is 

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a
a prime number
b
an even number
c
is a perfect square of a natural number
d
is an irrational number

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detailed solution

Correct option is C

The given series can be written as 31+14+142+......+P41+2.14+3.142+.....=8Use the sum of infinte GP and infinite AGP formulae ⇒3×11−14+P411−14+141−142=8 ⇒3×43+P443+14×169=84+P49=8P=9


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